Monday, July 19, 2010

Jim and Frank Mysteries Solutions - Puzzle #15 - Ticket Please

Yhe encrypted numbers are the square of each value, ie: 1,4,9,16,25,36,49,64,81 & 100. The encryption is the sum of each pair, ie: 1+4, 9+16, 25+36, 49+64, 81+100. The missing total is therefore 61.

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